You can use several ?? (null-coalescing) operators in a single expression. For example:
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| int result = i ?? j ?? k ?? 0; // i, j and k are all of type int? |
Notice that the final operand in the long expression is an integer constant. If we tried to use an int? variable as the final operand, we’d get a compile-time error indicating that we can’t implicitly convert the int? to an int. (Because the int?variable might be null, which can’t be assigned to an int).
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| int result = i ?? j ?? k; // Compile-time error |
Whenever you use this form of an expression with the ?? operator, assigning a value to a non-nullable type, the type of the 2nd operand must match the type of the variable being assigned to. (Or be implicitly converted to the target type).