You could use the DEBUG constant to conditionally include code in your program that outputs some debug information. This can get unwieldy, given that you need #if/#endif directives surrounding every line that outputs some debug information.
A cleaner way to output debug information only for Debug builds is to use the Debug.WriteLine method. (Debug is defined in the System.Diagnostics namespace).
Below is an example of a method that outputs some debug information.
1
2
3
4
5
6
7
8
| public void Bark(){ Debug.WriteLine("DEBUG INFO: Entering Dog.Bark() [{0}]", Name); Console.WriteLine("{0} says woof", Name); Debug.WriteLine("DEBUG INFO: Exiting Dog.Bark() [{0}]", Name);} |
To get this debugging output to go to a console window, you also need to define a listener that will direct the output of the Debug class to the console output window.
1
| Debug.Listeners.Add(new TextWriterTraceListener(Console.Out)); |
You’ll also need to include a using statement that references the System.Diagnostics namespace.